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10x^2-44x=-16
We move all terms to the left:
10x^2-44x-(-16)=0
We add all the numbers together, and all the variables
10x^2-44x+16=0
a = 10; b = -44; c = +16;
Δ = b2-4ac
Δ = -442-4·10·16
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-36}{2*10}=\frac{8}{20} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+36}{2*10}=\frac{80}{20} =4 $
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